runescape calculator (C++ Learning Community)

hey,
if any of you are familiar with the RPG runescape this is for you.
i dont really play the game at all any more but i decided to make this for practice.
this is a calculator for the mining skill in runescape. right now i just started and i only plan on doing levels 1-20 b/c up to 99 qould take way to long. and right now its only up to 2 levels but ill update

CODE

#include<iostream>
using namespace std;

int main()
{
char again = 'y';
while (again=='y' || again=='Y')

{
cout<<"..:Mining Calculator level 1-20::.."<<endl;
cout<<"Enter your desired level(1-20)"<<endl;
int lvl;
cin>>lvl;
switch(lvl)
{
int exp;
case 1: cout<<"Enter your current experience"<<endl;
cin>>exp;
cout<<"You need to gain "<<(83 - exp)<<endl;
break;
case 2: cout<<"Enter your current experience"<<endl;
cin>>exp;
cout<<"You need to gain "<<(174 - exp)<<endl;
break;
default: exit(0);
}

cout<<"Do you want to do it again?(Y/N)"<<endl;
cin>>again;
system("cls");
}
return 0;
}

and whoever it was who made the area program that helped me out with the again loop so thanks

As soon as I press enter, after entering my level, the program closes. You may want to fix that little problem. Or maybe I'm doing something wrong.

-Shadow382 :dj:

you would just have to add this

CODE

cin.get();

or this

CODE

system("pause");

to the end

[offtopic]
Don you said you wanted to see my bootsector when it's finished
well it's finished and posted 3 days now and you havent checked it yet
[/offtopic]

QUOTE (donprogc @ ++May 24 2005, 09:29 AM)

you would just have to add this

CODE

cin.get();

or this

CODE

system("pause");

to the end

A few weeks ago we had a problem with this (because of bad input).
Did we not come up with a solution that KTC was going to put in the FAQ after exams.

Without looking it up did it no go somthing like this:

CODE

if (!cin.good())
{
cin.<CORRECT BAD FLAG>();
}
cin.flush(); // or not
cin.get();

use cin.get()
it is alot better, it doesn't say : "press anykey....";

here:

CODE

#include<iostream>
using namespace std;

int main()
{
char again = 'y';
while (again=='y' || again=='Y')

{
cout<<"..:Mining Calculator level 1-20::.."<<endl;
cout<<"Enter your desired level(1-20)"<<endl;
int lvl;
cin>>lvl;
switch(lvl)
{
int exp;
case 1: cout<<"Enter your current experience"<<endl;
cin>>exp;
cout<<"You need to gain "<<(83 - exp)<<endl;
break;
case 2: cout<<"Enter your current experience"<<endl;
cin>>exp;
cout<<"You need to gain "<<(174 - exp)<<endl;
break;
default: exit(0);
}

cout<<"Do you want to do it again?(Y/N)"<<endl;
cin>>again;
cin.get();
}
return 0;
}

and then it rocks!
great job btw..

cin.ignore();

i recommend you add a "system("cls");" to the end of the loop (after cin.get). that way it doesn't take up much space in the console window

as well i could build up an include file that will make it work up to 99 then tell you how to use it (just to let you know at this point i havent started it yet)

QUOTE (donprogc++ @ May 24 2005, 02:29 PM)

you would just have to add this

CODE

cin.get();

or this

CODE

system("pause");

to the end

CODE

cin.get();

That won't work in some older compilers. I had an older version of Dev-C++ (I just upgraded) and it didn't accept cin.get(); as a valid function. I had to type system("PAUSE"); return 0;

QUOTE (Rmstn1580 @ Dec 5 2005, 12:21 AM)

That won't work in some older compilers. I had an older version of Dev-C++ (I just upgraded) and it didn't accept cin.get(); as a valid function. I had to type system("PAUSE"); return 0;

Remember it is in the standard namespace so you would need to use:

CODE

std::cin.get();

Or add a using statment.

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